A gun is fired vertically upwards from the top of an open truck moving horizontally at a uniform velocity of #50 ms^-1#. The bullet achieves a maximum height of 45m.
(i) State with reason whether or not the bullet will land on the truck.
(ii) Calculate the distance covered by the truck just before the bullet reaches the level from
which it was fired. (Use g=10 #ms^-2#).
Answer:
i)- The bullet will land on the track because it has the same horizontal velocity as the track
ii)
From s=ut+#1/2 at ^2#
where a will be replaced with g.,
For a free fall u=0,
s=#1/2at^2#
=>45=#1/2times10timest^2,#
t=3 seconds.
total time=3x2=6 seconds
Horizontal distance
=#v times t=50times6#
=300m
ii)
From s=ut+#1/2 at ^2#
where a will be replaced with g.,
For a free fall u=0,
s=#1/2at^2#
=>45=#1/2times10timest^2,#
t=3 seconds.
total time=3x2=6 seconds
Horizontal distance
=#v times t=50times6#
=300m
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